4/3x^2-3=2/3x^2-15

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Solution for 4/3x^2-3=2/3x^2-15 equation: 


x in (-oo:+oo)

(4/3)*x^2-3 = (2/3)*x^2-15 // - (2/3)*x^2-15

(4/3)*x^2-((2/3)*x^2)-3+15 = 0

(4/3)*x^2+(-2/3)*x^2-3+15 = 0

2/3*x^2 = -12 // : 2/3

x^2 = -18

x belongs to the empty set

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